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Latest post Tue, Mar 4 2008 12:11 PM by Zhao_the_Passerby. 5 replies.
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Anonymous  +  483367 Fri, 29 Feb 08 10:05 PM

A goat is tethered to the outside wall of a circular silo 20 feet in diameter.  If the length of the tether is such that it will wind halfway around the silo, how large an area around the silo is the goat able to graze on?

Because the silo is round and a different size then the circle of eating area you can't just use the eating area as half of a circle.  My friend says the answer is 2,580 Square Feet of "goat eatin' area", but I do not get that number.  Any ideas?

Akavall  +  483439 Sat, 01 Mar 08 02:54 AM

I am getting a different number.

Silo has a circumference of 62.8 (20 * 3.14)

Thether is 31.4 (62.8/2)

The area of the circle where the goat can feed is 3095.91 (31.4^2)*3.14 minus the area of the silo, which is 314 (10^2)*3.14

3095.91 - 314 = 2781.91 sq. feet

Joined on Sat, Nov 24 2007
Full Member 137
Zhao_the_Passerby  +  483821 Sun, 02 Mar 08 12:50 AM
Akavall

I am getting a different number.


Silo has a circumference of 62.8 (20 * 3.14)


Thether is 31.4 (62.8/2)


The area of the circle where the goat can feed is 3095.91 (31.4^2)*3.14 minus the area of the silo, which is 314 (10^2)*3.14


3095.91 - 314 = 2781.91 sq. feet



Sorry I don't think that your answer is correct.

The outer curve is not a round circle, since the silo would bend the tether.
Joined on Tue, Jan 15 2008
China
New Member 31
I long ago lost a hound, a bay horse and a turtle dove, and am still on their trail. --Thoreau
Akavall  +  483840 Sun, 02 Mar 08 03:57 AM

Good observation! So the correct answer is smaller than mine, which makes 2,580 look like a right answer. I wonder how they got it, though.

Anonymous, 1 yr 265 days ago

Well, surely the goat can then walk one way, half way around the silo, then half way the other way around the silo, meaning he can graze in the entire area.
Zhao_the_Passerby  +  484799 Tue, 04 Mar 08 12:11 PM
Since it is a riddle, not a math question, integrating method in math or similar concepts should not be used, IMO. And I can't find a way to solve it.
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