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<?xml-stylesheet type="text/xsl" href="http://www.englishforums.com/utility/FeedStylesheets/rss.xsl" media="screen"?><rss version="2.0" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:slash="http://purl.org/rss/1.0/modules/slash/" xmlns:wfw="http://wellformedweb.org/CommentAPI/"><channel><title>Search results for 'user:Praveen?khm'</title><link>http://www.englishforums.com/search/pro.htm?q=user%3aPraveen%3fkhm&amp;o=DateDescending</link><description>Search results for 'user:Praveen?khm'</description><dc:language>en-US</dc:language><generator>XMOD (Build: 3607.32596)</generator><item><title>Re: Cut the gold bar twice and pay for 7 days.....</title><link>http://www.englishforums.com/English/CutGoldTwiceDays/cljpg/post.htm#223954</link><pubDate>Tue, 09 May 2006 12:37:41 GMT</pubDate><guid isPermaLink="true">946f00bb-57d3-4b7b-a9a2-059b5341af52:223954</guid><dc:creator>praveen_khm</dc:creator><description>Cool.... 

 you got it ...but am disappointed that you solved it so soon......  

 -Pravi.....</description></item><item><title>Cut the gold bar twice and pay for 7 days.....</title><link>http://www.englishforums.com/English/CutGoldTwiceDays/cljpg/post.htm</link><pubDate>Tue, 09 May 2006 12:17:18 GMT</pubDate><guid isPermaLink="true">946f00bb-57d3-4b7b-a9a2-059b5341af52:223947</guid><dc:creator>praveen_khm</dc:creator><description>Hi all, 
 Try answering this one which I found in one of the other sites....... 
 You employ someone to work for you for seven days. To pay your employee, you have one bar of gold which is has seven segments. Your employee needs to be paid for their days work at the end of each day. You may only cut the gold bar twice. How do you pay your employee? 
  
 Pravi......</description></item><item><title>Re: Cricket Puzzle.....</title><link>http://www.englishforums.com/English/CricketPuzzle/clcll/post.htm#222058</link><pubDate>Wed, 03 May 2006 10:42:39 GMT</pubDate><guid isPermaLink="true">946f00bb-57d3-4b7b-a9a2-059b5341af52:222058</guid><dc:creator>praveen_khm</dc:creator><description>Eargasms, 
 That was a nice try.... However, for the first try, when a person hits a six, no matter what he runs, he has to face the ball again. So no question of the other player facing the ball. For your second try, when he is awarded 5 runs, again the run which he runs again will not be considered. 
 Cheers, 
 Pravi.......</description></item><item><title>Re: Cricket Puzzle.....</title><link>http://www.englishforums.com/English/CricketPuzzle/clcll/post.htm#221907</link><pubDate>Tue, 02 May 2006 19:25:26 GMT</pubDate><guid isPermaLink="true">946f00bb-57d3-4b7b-a9a2-059b5341af52:221907</guid><dc:creator>praveen_khm</dc:creator><description>Hello friends, 
 Can someone let me know if you're not able to understand the puzzle...or if it is not clear...... 
 I was expecting my first thread to be interesting...but did not find any responses..... 
 let me wait....</description></item><item><title>Cricket Puzzle.....</title><link>http://www.englishforums.com/English/CricketPuzzle/clcll/post.htm</link><pubDate>Tue, 02 May 2006 15:16:08 GMT</pubDate><guid isPermaLink="true">946f00bb-57d3-4b7b-a9a2-059b5341af52:221861</guid><dc:creator>praveen_khm</dc:creator><description>Hi, I am posting my first puzzle here. . 
 This is a cricket puzzle. 
 There are two balls left for the match to be completed. Each player on either side are at 94 runs. At the end of the match, both score a century. 
 Can someone guess how would that be possible??? 

 -Pravi</description></item><item><title>Re: Hope you can help me...</title><link>http://www.englishforums.com/English/HopeYouCanHelpMe/ckmrv/post.htm#221784</link><pubDate>Tue, 02 May 2006 10:55:56 GMT</pubDate><guid isPermaLink="true">946f00bb-57d3-4b7b-a9a2-059b5341af52:221784</guid><dc:creator>praveen_khm</dc:creator><description>Hey, 
 I am a new member for this forum. This is the first puzzle am trying to solve. I would try for 5. 

 Take 10 coins and drop five in each of the container. The three choices are: Either they are equal, the one in the right is heavier or the one in the left is heavier. If they are equal, weigh the remaining two which gives the desired result. Else, choose 4 coins from the lighter container and weigh two in each container. They can again be equal or one of the containers may have the lighter coin. If equal, the left out is the counterfeit. Else, weigh the coins again which are in the lighter container. 
 Hope this solves.....</description></item></channel></rss>