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Context:

Methods We assessed the family and medical histories of 84 children (63 boys and 21 girls) with idiopathic cardiac hypertrophy diagnosed before 15 years of age (mean [±SD] age, 6.99±6.12 years). We sequenced eight genes: MYH7, MYBPC3, TNNT2, TNNI3, TPM1, MYL3, MYL2, and ACTC. These genes encode sarcomere proteins that, when mutated, cause adult-onset cardiomyopathies. We also sequenced PRKAG2 and LAMP2, which encode metabolic proteins; mutations in these genes can cause early-onset ventricular hypertrophy.

Does (mean [±SD] age, 6.99±6.12 years) mean (average age = 6.99±6.12 years of old)? SD = Standard deviation?
Comments  
Exactly, mean age = average age, SD= Standard deviation. Emotion: smile
Thank you.

Would any native English speaker like to reconfirm this?
Students: We have free audio pronunciation exercises.
Hey NL, you can trust Francesca on this. She is a scientist well-schooled in statistics and has even presented scientific papers in English, including one at the prestigious MIT. If she answers ANYTHING about science, statistics, and especially the fascinating topic of algae, you can take her answer to the bank.
Thanks Barb Emotion: embarrassed[K]

In fact, NL888, mean and SD (in English) are my "daily bread" despite I'm not a native speaker Emotion: wink
Thank you GG and Francesca.

I hope more and more scientists will be around in this forum.Emotion: smile
Students: Are you brave enough to let our tutors analyse your pronunciation?
I've got a the same question (I think) but the answer is not clear for me. (excuse my english..also from NL ;-)
When it's says: "The mean ± SD age at the onset of symptoms was 24.40 ±
8.58 years (range 10-46)" Does it mean: The average onset of symptoms is: 24.40 with a range from 8.58 (average)before that age and 8.58 (average) older then that age?

(the onset of symtoms can't be 8.58 in this case)

I don't get it...is my thinking right?